Given an integer array nums, move all 0's to the end of it while maintaining the relative order of the non-zero elements.
Note that you must do this in-place without making a copy of the array.
Example 1:
Input: nums = [0,1,0,3,12] Output: [1,3,12,0,0]
Example 2:
Input: nums = [0] Output: [0]
Constraints:
1 <= nums.length <= 104-231 <= nums[i] <= 231 - 1
Follow up: Could you minimize the total number of operations done?
SOL:
參考李根逸博士的影片,loop整個nums,若遇到非零的元素則存回nums(從index 0開始存),因為非零的個數一定少於整個nums,所以可以使用in-place的方式,把非零者直接存回nums。
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